Prove that the CHSH inequality is violated by given quantum states and measurements of A and B

by winner   Last Updated July 12, 2019 09:19 AM - source

given A and B share EPR pairs 1/√2 (|00⟩+|11⟩)

Here EPR state is shared by A and B, where A is the 1st-qubit while B is the 2nd-qubit. They are free to measure their own qubit with the following measurement settings

A measures with (|0⟩,|1⟩) or (|+⟩,|−⟩)

B measures with (sin(3π/8)|0⟩+cos(3π/8)|1⟩, -sin(π/8)|0⟩+cos(π/8)|1⟩) or (sin(π/8)|0⟩+cos(π/8)|1⟩,-sin(3π/8)|0⟩+cos(3π/8)|1⟩)

Here,

|+⟩=1√2(|0⟩+|1⟩)

|−⟩=1√2(|0⟩−|1⟩)



Related Questions



'Happy Death Day' and Quantum Mechanics

Updated August 26, 2018 23:19 PM


MATLAB GPU-enabled functions list

Updated January 15, 2019 20:19 PM