If A is non-empty set then how may " transitive relation " can be made by A×A ?
There is no simple way to get a solution but you can interpretate your problem in this way:
For each relation $\sim$ of $A$ we can define the map
$\psi_\sim: A\to \mathcal{P}(A)$
such that
$\psi_\sim(a):=\{b\in A: a\sim b\}$
In this case you have that if $\sim$ is transitive then for each $b\in \psi_\sim(a)$
$\psi_\sim(b)\subseteq \psi_{\sim}(a)$
So
$\{\sim : \sim transitive \}\cong \Lambda$
where $\Lambda:= \{\psi:A\to \mathcal{P}(A): \forall a,b \ if \ b\in \psi(a) \ then \ \psi(b)\subseteq \psi(a)\}$
Now we want prove to determine the cardinality of $\Lambda$. For simplicity $A=\{1,\dots , n\}$
We suppose that $\psi(i)=A$ for each $i< n$ then the only choice of $\psi(n)$ to get $\psi$ transitive can be $\psi(n)=\{n\}$ or $\psi(n)=A$. So in this case we have
$|\{\psi\in \Lambda : \psi(i)=A \forall i< n\}|=2$
We suppose that $\psi(n-1)=\{1,\dots n-1\}$ while $\psi(i)=A$ for each $i<n-1$ . Then